How it works
The arithmetic mean (average) is the sum of values divided by how many values there are — the balance point of a set of numbers on a number line. This calculator accepts five inputs (all included in the calculation) and reports the mean, sum, count, minimum and maximum. Worked example: 10, 20, 30, 40, 50. Sum = 150. Count = 5. Average = 150 ÷ 5 = 30. Min = 10, max = 50. The mean is sensitive to outliers: replacing 50 with 500 jumps the average from 30 to 120 while the median would move modestly. For skewed data (income, home prices), median or trimmed mean often describes 'typical' better than raw average. Weighted average — where values count differently — is what the GPA calculator implements; this tool assigns equal weight to each entry. Enter zero explicitly if a value is truly zero; the engine counts all five fields. For larger datasets, spreadsheet functions (AVERAGE, MIN, MAX) scale better, but five-number quick checks suit test scores, lab repeats and weekly spending snapshots.
Formula
Average = (v1 + v2 + v3 + v4 + v5) ÷ 5 | Sum = v1 + … + v5
Tips
- Check min and max before trusting the average — one outlier can dominate the mean.
- For unequal importance, use weighted averages (GPA tool) instead of this simple mean.
- Median may describe 'typical' better when one value is far from the rest.
- Negative values are allowed — useful for net changes or temperature swings.
Frequently asked questions
- What is the average of 10, 20, 30, 40 and 50?
- Sum = 150, divided by 5 values = 30.
- What is the difference between mean and median?
- Mean is sum ÷ count. Median is the middle value when sorted. For 10,20,30,40,50 the median is also 30; with an outlier they diverge.
- Are all five fields required?
- The engine averages all five inputs on the form. Enter zero for unused slots if you want a shorter list averaged — or use only the values you need and adjust mentally.
- Can I average percentages?
- Only if each percentage refers to the same whole or sample size. Averaging percents from different denominators requires a weighted approach.